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Aptitude

Simple & Compound Interest

Formulas to Solve Simple interest Problems

Simple interest is a easy method of calculating the interest charge on a loan.
It is calculated by multiplying the daily interest rate  by the principal by the number of days that elapse between payments
i.e.  $\frac{PTR}{100}$

Formulas for Compound Interest

Compound interest is the interest on interest to the principal sum of a amount.
It is calculated by ; result of reinvesting interest, rather than paying it out. By this interest in the next period is ; earned on the principal sum plus previously accumulated interest.

Simple Interest Formulas

  • Simple Interest is the rate at which we lend or borrow money. Suppose we borrow some money from the bank then to repay the amount we need to pay certain extra money.That extra amount of money is called interest.
    The interest on a sum borrowed for a certain period is called simple interest.
  • Simple interest is calculated by multiplying the daily interest rate by the principal by the number of days that elapse between payments.
  • This type of interest usually applies to short-term loans.
  • $Basic$ $Formula$ $=\frac{P T R}{100}$

  • SI = $\frac{P×R×T}{100}$

    Where,

    P = Money borrowed or lent out for a certain period(principal)

    R = Rate of interest

    T = Time period for which the amount is lent

    Principal = $\frac{100 × SI}{R×T}$

    Rate = $\frac{100 × SI}{P×T}$

    Time = $\frac{100 × SI}{R×P}$

To get total amount of money :
  • Amount = Principal + Interest
  • A = P + I
Formulas based Questions on Simple Interest

Example 1. Find the simple interest on Rs. 65,000 at 6(2/3)% per annum for a period of 9 months?

Options

(A) 3520
(B) 3250
(C) 2350
(D) 5320

Solution

Principle = 65,000

$Rate = 6\frac{2}{3}$

Time = 9 months

Principle = 65,000

Rate = $\frac{20}{3}$

Time = $\frac{3}{4}$

S.I = $\frac{P×R×T}{100}$

= Rs. $[65000×(\frac{20}{3})×(\frac{3}{4})×(\frac{1}{100})]$

= 3250

Correct Option(B)

Example 2. What sum of money will amount to Rs. 520 in 5 years and Rs. 568 in 7 years at simple interest?

Options

(A) 350

(B) 400

(C) 550

(D) 500

Solution

Amount in $5$ years = Rs $520$

Amount in $7$ years = Rs $568$

$2$ years S.I = $568-520$ = $48$

Simple Interest for $1$ years = $\frac{48}{2}$ = 24

$5$ years amount = Rs $520$

For $1$ years = $5×24$ = $120$

$P = A – S.I$ = $520-120$

$P = 400$

Correct Option(B)

Compound Interest
  • Compound interest is the interest calculated on the original principal and on the accumulated past interest of a deposit or loan. Compound interest is calculated based on the principal, interest rate (APR or annual percentage rate), and the time involved.

Formula of Compund Interest (CI) = $P (1+\frac{r}{100n})^{nT}$

Formula of Amount = CI +P $= P (1+\frac{r}{100n})^{nT}+P$

Here, $P$ = Principal

$r$ = rate of interest

$T$ = the number of years the amount is deposited or borrowed for.

$n$ = the number of times that interest is compounded per unit $t$.

Important Compound Interest formulas
Formulas for Compound Interest (When Interest is Compound Annually)

  • $Amount = P(1+\frac{r}{100})^T$
  • Compound Interest =Total amount – Principal
  • Rate of interest (R) = $[(\frac{A}{P})^{\frac{1}{T}}-1]$%

Formulas of Compound Interest (When Interest is Compound Half Yearly)

  • $Amount = P(1+\frac{\frac{r}{2}}{100})^{2T}$
  • Compound Interest =Total amount – Principal

Compound Interest Formulas (When Interest is Compound Quarterly)

  • $Amount = P(1+\frac{\frac{r}{4}}{100})^{4T}$
  • Compound Interest =Total amount – Principal

Formulas of Compound Interest (When Interest is Compound Monthly)

  • $Amount = P(1+\frac{\frac{r}{12}}{100})^{12T}$

Compound Interest Formulas (When Interest is Compounded Annually but time is in fraction, say $2(\frac{3}{2})years$ )

  • $Amount = P(1+\frac{r}{100})^2$ $(1+\frac{\frac{3}{2}r}{100})^{12T}$

Formulas of Compound Interest (When rates are different for different years)

  • $Amount = P(1+\frac{r_{1}}{100})(1+\frac{r_{2}}{100})(1+\frac{r_{3}}{100})$

Formulas for Compound Interest (Present worth of Rs. x due n years)

  • $Present$ $worth = (\frac{x}{1+\frac{1}{100}})$

Problems Based on Formulas of Compound interest with solutions

Question 1 . Find the amount on Rs 16000 for 3 year at 5% per annum compounded annually n.

(A) Rs. 18562

(B) Rs. 18550

(C) Rs. 18952

(D) Rs. 18552

Solution :

According to the formula of Compound Interest

Amount = $P(1+\frac{r}{100})^n$

Amount = $16000(1+\frac{5}{100})^3$

Amount = $16000(1+\frac{1}{20})^3$

Amount = $16000(\frac{21}{20})^3$

Amount =18552

Correct Option: D

Question 2 . Find the compound interest on Rs. 10,000 at 20% per annum for 5 years 4 months, compounded annually is ?

(A) Rs. 16600

(B) Rs. 16544

(C) Rs. 15644

(D) Rs. 16500

Solution :

According to the Formula of Compound Interest ,

CI = $P(1+\frac{r}{100})^n$

CI = $10,000(1+\frac{20}{100})^{5\frac{1}{3}}$

CI = $10,000(1+\frac{1}{5})^{5\frac{1}{3}}$

CI = $10,000(1+\frac{1}{5})^5(1+\frac{1}{3×5})$

CI = $10,000(1+\frac{1}{5})^5(1+\frac{1}{15})$

CI = $10,000(\frac{6}{5})^5(\frac{16}{15})$

On Solving ,

CI = $26544 – 10,000$

CI = $16544$

Correct Option: B