×
>
<

Aptitude

Introduction to Surds and Indices

How to Solve Surds and Indices Questions Quickly

The natural number which cannot be expressed in the form of fraction known as Surds.

For example:$ \sqrt{2}=2^{\frac{1}{2}}$ and the Indices refers to the power to which a number is raised.

Surds: Number which cannot be expressed in the fraction form of two integers is called as surd.

Indices: Indices refers to the power to which a number is raised. For example; 2²

Sample Solutions Regarding the Rules of Surds and Indices :
Indices Multiplication rules:-

  • Multiplication rule with same base

    $a^n ⋅ a^m = a^{(m+n)}$

    Example:

    $2_{3} ⋅ 2_{4} = 2^(3+4) = 2^7 = 2⋅2⋅2⋅2⋅2⋅2⋅2 = 128$

Surds Multiplication rules:-

  • Multiplication rule with same indices

    $a^n ⋅ b^n = (a ⋅ b)^n$

    Example:

    $3^2 ⋅ 2^2 = (3⋅2)^2 = 36$

Indices Division rules:-

  • Division rule with same indices

    $ \frac{a^n}{b^n} = (\frac{a}{b})^n$

    Example:

    $ \frac{9^3}{3^3} = (\frac{9}{3})^3 = 27$

Surds and Indices Power rules

  • Power rule 1

    $(a^n)^m = a^{(n.m)}$

    Example:

    $(2^3)^2 = 2^{(3.2)} = 26 = 2⋅2⋅2⋅2⋅2⋅2 = 64$

  • Power rule 2

    $ a^{n^m} = a^{(n^m)}$

    Example:

    $2^{3^2} = 2^{(3^2)} = 29 = 2⋅2⋅2⋅2⋅2⋅2⋅2⋅2⋅2 = 512$

Type 1: How to Solve Surds and Indices Quickly- Simplify the expression

1. 1. Find the value of $7^{-25} – 7^{-26}$

Options:

A. $6 × 7^{-26}$

B. $6 × 7^{-25}$

C. $6 × 7^{-26}$

D. $7 × 7^{-26}$

Solution:

$7^{-25} – 7^{-26} = \frac{1}{7^{25}} – \frac{1}{7^{26}}$

$\frac{7 – 1}{7^{26}} = 6 × 7^{-26}$

Correct option: A

2. Simplify $(256)^ \frac{3}{4}$

Options:

A. 16

B. 12

C. 256

D. 64

Solution:

$(256)^ \frac{3}{4} = (44)^ \frac{3}{4} = 4^3 = 64$

Correct option: D

3.Find the value of $8^{112} ÷ 8^{110}$

Options:

A. 72

B. 64

C. 81

D. 49

Solution:

We know,

$\frac{a^m}{a^n} = a^(m-n)

1480 = 2 x 2 x 2 × 5 × 37

= 8 ^ {(112 – 110)}

= 8^2 = 64

Correct Option: B

Type 2: Solve Surds and Indices Quickly- Find the value of x

1. If 4x + 1 = 80, then the value of x is

Options:

A. 16

B. 9

C. 25

D. 4

Solution:

$4^x(1 + 4) = 80$

$4^x * 5 = 80$

$4^x = \frac{80}{5}$

$4^x = 16$

x = 2

$x^x = 2^2 = 4$

Correct option: D

2. If $2^a = 3\sqrt{32}$ , then a is equal to:

Options:

A.$\frac{1}{3}$

B. 4

C. $\frac{5}{3}$

D. $\frac{1}{2}$

Solution:

Given value $2^a$

$3\sqrt{32}$

$2^a = (32)^ \frac{1}{3}$

$2^a = (2^5)^ \frac{1}{3}$

$2^a = (2)^ \frac{5}{3}$

$a = \frac{5}{3}$

Correct option: C

3.Let x and y be two positive real numbers such that $xy=1$. The minimum value of x+y is

Options:

A. 1

B. $\frac{1}{2}$

C. 2

D. $\frac{1}{4}$

Solution:

Given $x \times \text{y = 1 and f(x,y) = x + y }$

$f(x) = x+\frac{1}{x}$

$f(x) = 1 = \frac{1}{{x}^2}$

For maxima or minima,

$f'(x) = 0$

$x = ±1 $

$f''(x) = \frac{2}{{x}^3}$

$f''(x) > 0 at x = 1$

$f(1)=2$

So, minimum value of $\text{ x+y is 2 }.$

Correct Option: C